Start your free trial In partnership withThe cylinder formed by the graph of x^2 y^2 = 4 and the planes z=0 and z=4 has a density at each point equal to z find the mass of the cylinder Expert Answer Previous question Next questionSurfaces and Contour Plots Part 4 Graphs of Functions of Two Variables The graph of a function z = f(x,y) is also the graph of an equation in three variables and is therefore a surfaceSince each pair (x,y) in the domain determines a unique value of z, the graph of a function must satisfy the "vertical line test" already familiar from singlevariable calculus
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Graph of cylinder x^2+y^2=4
Graph of cylinder x^2+y^2=4-Graph x^22y^2=4 x2 2y2 = 4 x 2 2 y 2 = 4 Find the standard form of the ellipse Tap for more steps Divide each term by 4 4 to make the right side equal to one x 2 4 2 y 2 4 = 4 4 x 2 4 2 y 2 4 = 4 4 Simplify each term in the equation in order to set the right side equal to 1 1See the answer cylinder x^2y^2=4 and surface z=xy Find the vector function that
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By using Pythagoras you would end up with the equation given where the 4 is in fact r2 To obtain the plot points manipulate the equation as below Given x2 y2 = r2 → x2 y2 = 4 Subtract x2 from both sides giving y2 = 4 −x2 Take the square root of both sides y = √4 − x2 Now write it as y = ± √4 −x2Question Cylinder X^2y^2=4 And Surface Z=xyFind The Vector Function That Represents The Intersection Of The Two Surfaces This problem has been solved!Related » Graph » Number Line » Examples » Our online expert tutors can answer this problem Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!
Graph x^2y^2=4 x2 − y2 = 4 x 2 y 2 = 4 Find the standard form of the hyperbola Tap for more steps Divide each term by 4 4 to make the right side equal to one x 2 4 − y 2 4 = 4 4 x 2 4 y 2 4 = 4 4 Simplify each term in the equation in order to set the right side equal to 1 1 The standard form of an ellipse or hyperbola requires
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